MATH SOLVE

4 months ago

Q:
# mars, inc. claims that 20% of its m&m plain candies are orange. a sample of 100 such candies is randomly selected. find the mean and standard deviation for the number of orange candies in such groups of 100.

Accepted Solution

A:

The probability p of an orangecandy is 0.2. The sample size = 100.

The mean is given by:

[tex]n\times p=100\times0.2=20[/tex]

The standard deviation is given by:

[tex] \sqrt{npq} = \sqrt{100\times0.2\times(1-0.2)} =4[/tex]

The answers are: Mean = 20. Standard deviation = 4.

The mean is given by:

[tex]n\times p=100\times0.2=20[/tex]

The standard deviation is given by:

[tex] \sqrt{npq} = \sqrt{100\times0.2\times(1-0.2)} =4[/tex]

The answers are: Mean = 20. Standard deviation = 4.