Q:

Determine the solution for x2 + 36 > 12x

Accepted Solution

A:
[tex]\huge\text{Hey there!}[/tex][tex]\large\boxed{\mathsf{x^2 + 36 > 12x}}[/tex][tex]\large\text{SUBTRACT 12x to BOTH SIDES.}[/tex][tex]\large\boxed{\mathsf{\rightarrow x^2 + 36 - 12x = 12x - 12x}}[/tex][tex]\large\text{SIMPLIFY IT!}[/tex][tex]\large\text{NEW EQUATION: }\large\boxed{\mathsf{x^2 - 12x + 36 = 0}}[/tex][tex]\large\text{FACTOR the LEFT side: \boxed{\mathsf{(x - 6)(x - 6) = 0}}}[/tex][tex]\large\text{We get: \boxed{\mathsf{x = 6}}}[/tex][tex]\large\text{CHECK to make sure you have intervals with the equations.}[/tex][tex]\large\text{Either of these inequalities should work with your given inequality}\downarrow[/tex][tex]\large\text{YOUR ANSWERS..}[/tex][tex]\large\boxed{\mathsf{x > 6}}\\\\\large\boxed{\mathsf{x < 6}}[/tex][tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]~[tex]\frak{Amphitrite1040:)}[/tex]