If f(x) = x2 - 2x and g(x) = 6x + 4, for which value of x does (f+g)(x) = 0?
Accepted Solution
A:
Answer:-2Step-by-step explanation:Let's plug your functions f(x)=x^2-2x and g(x)=6x+4 into (f+g)(x)=0 and then solve your equation for x.So (f+g)(x) means f(x)+g(x).So (f+g)(x)=x^2+4x+4Now we are solving (f+g)(x)=0 which means we are solve x^2+4x+4=0.x^2+4x+4 is actually a perfect square and is equal to (x+2)^2.So our equation is equivalent to solving (x+2)^2=0.(x+2)^2=0 when x+2=0.Subtracting 2 on both sides gives us x=-2.